The correct order of increasing s-character ( | vedclass

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(A) To determine the $s$-character,we first identify the hybridization of the central atom in each species:$(I) \, CO_3^{2-}: C$ is $sp^2$ hybridized

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$II < III < IV < I < V$

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(A) To determine the $s$-character,we first identify the hybridization of the central atom in each species:$(I) \, CO_3^{2-}: C$ is $sp^2$ hybridized ($33.3\% \ s$-character).$(II) \, XeF_4: Xe$ is $sp^3d^2$ hybridized ($16.6\% \ s$-character).$(III) \, I_3^-: I$ is $sp^3d$ hybridized ($20\% \ s$-character).$(IV) \, NCl_3: N$ is $sp^3$ hybridized ($25\% \ s$-character).$(V) \, BeCl_2: Be$ is $sp$ hybridized ($50\% \ s$-character).Comparing the percentages: $sp^3d^2 (16.6\%) Thus,the correct order is $(II) < (III) < (IV) < (I) < (V)$.

The correct order of increasing $s$-character (in percentage) in the hybrid orbitals of the following molecules/ions is: $(I) \, CO_3^{2-}$,$(II) \, XeF_4$,$(III) \, I_3^-$,$(IV) \, NCl_3$,$(V) \, BeCl_2$.

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