The correct order of the following 3d metal o | vedclass

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(A) Calculate the oxidation state of the metal in each oxide:$(a)$ In $CrO_3$: $x + 3(-2) = 0 \implies x = +6$$(b)$ In $Fe_2O_3$: $2x + 3(-2) = 0 \imp

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$(a) > (d) > (c) > (b) > (e)$

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(A) Calculate the oxidation state of the metal in each oxide:$(a)$ In $CrO_3$: $x + 3(-2) = 0 \implies x = +6$$(b)$ In $Fe_2O_3$: $2x + 3(-2) = 0 \implies 2x = +6 \implies x = +3$$(c)$ In $MnO_2$: $x + 2(-2) = 0 \implies x = +4$$(d)$ In $V_2O_5$: $2x + 5(-2) = 0 \implies 2x = +10 \implies x = +5$$(e)$ In $Cu_2O$: $2x + 1(-2) = 0 \implies 2x = +2 \implies x = +1$Comparing the oxidation states: $(a) (+6) > (d) (+5) > (c) (+4) > (b) (+3) > (e) (+1)$.Thus,the correct order is $(a) > (d) > (c) > (b) > (e)$.

The correct order of the following $3d$ metal oxides,according to their oxidation numbers is:
$(a)$ $CrO_3$ $(b)$ $Fe_2O_3$ $(c)$ $MnO_2$ $(d)$ $V_2O_5$ $(e)$ $Cu_2O$

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The correct order of the following $3d$ metal oxides,according to their oxidation numbers is:$(a)$ $CrO_3$ $(b)$ $Fe_2O_3$ $(c)$ $MnO_2$ $(d)$ $V_2O_5$ $(e)$ $Cu_2O$