The correct order of dipole moment of the mol | vedclass

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(A) Dipole moment is a vector quantity. It is defined as the product of the magnitude of the charge and the distance between the centers of the positi

Vedclass · Accepted Answer

$III > I > IV > II$

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(A) Dipole moment is a vector quantity. It is defined as the product of the magnitude of the charge and the distance between the centers of the positive and negative charges.Dipole moment of $NF_3$ and $NH_3$: The dipole moment of $NH_3$ $(1.46 \ D)$ is larger than $NF_3$ $(0.24 \ D)$ because in $NH_3$,the dipole moment vector of the $N-H$ bonds and the lone pair are in the same direction,while in $NF_3$ molecule,the dipole moment vector of the lone pair and the $N-F$ bond pairs are in opposite directions.Dipole moment of $H_2O$ and $NH_3$: Both have dipole moments due to their bent and pyramidal geometries respectively. The dipole moment of $H_2O$ $(1.85 \ D)$ is greater than $NH_3$ because $O$ is more electronegative than $N$.Dipole moment of $BF_3$: It is zero because it has a symmetrical trigonal planar structure.Therefore,the correct order of dipole moments is $H_2O$ $(III)$ > $NH_3$ $(I)$ > $NF_3$ $(IV)$ > $BF_3$ $(II)$.

The correct order of dipole moment of the molecules $NH_3$ $(I)$,$BF_3$ $(II)$,$H_2O$ $(III)$,$NF_3$ $(IV)$ is

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