The correct order of boiling points of H_2O, | vedclass

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(D) All the elements of Group $16$ form hydrides of the type $H_2E$ (where $E = O, S, Se, Te, Po$).Boiling point depends on the molecular mass and int

Vedclass · Accepted Answer

$H_2O > H_2Te > H_2Se > H_2S$

Vedclass · Answer

(D) All the elements of Group $16$ form hydrides of the type $H_2E$ (where $E = O, S, Se, Te, Po$).Boiling point depends on the molecular mass and intermolecular forces.As the size of the central atom increases,the van der Waals forces increase,which generally leads to an increase in boiling point from $H_2S$ to $H_2Te$.However,$H_2O$ exhibits exceptionally high boiling point due to the presence of strong intermolecular hydrogen bonding.Therefore,the correct order of boiling points is $H_2O > H_2Te > H_2Se > H_2S$.

The correct order of boiling points of $H_2O, H_2S, H_2Se$ and $H_2Te$ respectively is

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