Correct decreasing order of boiling point of | vedclass

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(C) The boiling point of these compounds is primarily determined by the strength of intermolecular hydrogen bonding.$H_2O$ has the highest boiling poi

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$II > III > IV > I$

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(C) The boiling point of these compounds is primarily determined by the strength of intermolecular hydrogen bonding.$H_2O$ has the highest boiling point because each molecule can form up to $4$ hydrogen bonds,creating a strong three-dimensional network.$HF$ has the next highest boiling point due to strong hydrogen bonding,though it forms fewer bonds per molecule than $H_2O$.$NH_3$ has a lower boiling point than $HF$ because the electronegativity difference between $N$ and $H$ is smaller,leading to weaker hydrogen bonds.$HCl$ does not exhibit significant hydrogen bonding and relies on dipole-dipole interactions,resulting in the lowest boiling point among the given compounds.Therefore,the decreasing order is $II > III > IV > I$.

Correct decreasing order of boiling point of given compounds:
$I. \ HCl$
$II. \ H_2O$
$III. \ HF$
$IV. \ NH_3$

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Correct decreasing order of boiling point of given compounds:$I. \ HCl$$II. \ H_2O$$III. \ HF$$IV. \ NH_3$