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(B) The boiling point elevation is a colligative property,which depends on the number of particles in the solution. $BaCl_2$ dissociates as $BaCl_2 \r

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$t_1 > t_2$

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(B) The boiling point elevation is a colligative property,which depends on the number of particles in the solution. $BaCl_2$ dissociates as $BaCl_2 \rightarrow Ba^{2+} + 2Cl^-$,providing $3$ ions per formula unit. $KCl$ dissociates as $KCl \rightarrow K^+ + Cl^-$,providing $2$ ions per formula unit. Since $BaCl_2$ produces more ions than $KCl$ at the same molarity,it has a higher van't Hoff factor $(i)$,leading to a greater elevation in boiling point. Therefore,$t_1 > t_2$.

Mark the correct relationship between the boiling points of very dilute solutions of $BaCl_2$ $(t_1)$ and $KCl$ $(t_2)$,having the same molarity.

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