The correct order of 2^{nd} ionisation potent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configura

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(C) The $2^{nd}$ ionisation potential corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.The electronic configurations of the unipositive ions are:$C^+ (1s^2 2s^2 2p^1)$$N^+ (1s^2 2s^2 2p^2)$$O^+ (1s^2 2s^2 2p^3)$$F^+ (1s^2 2s^2 2p^4)$$O^+$ has a stable half-filled $2p^3$ configuration,which makes it very difficult to remove the second electron,resulting in the highest $2^{nd}$ ionisation potential.Comparing the others,$F^+$ has a higher effective nuclear charge than $N^+$,and $N^+$ has a higher effective nuclear charge than $C^+$.Thus,the correct order is $O > F > N > C$.

The correct order of $2^{nd}$ ionisation potential of carbon,nitrogen,oxygen and fluorine is

Similar Questions

The first ionization enthalpies of $N$ and $O$ are respectively....... $eV$.

Among $Be$,$B$,$Mg$ and $Al$,the second ionisation potential is maximum for

In the photoelectric effect,if the work functions of $Li$,$Na$,and $Rb$ are $2.41 \ eV$,$2.30 \ eV$,and $2.09 \ eV$ respectively,the work function of $K$ could approximately be in $eV$?

The ionization potential of sodium is $5.48 \ eV$. The $I.P.$ of potassium is ............. $eV$

Which one of the following has the lowest ionization energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module