In the photoelectric effect,if the work funct | vedclass

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(B) The work function is the minimum energy required to remove an electron from the surface of a metal. As the atomic size increases down a group,the

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$2.20$

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(B) The work function is the minimum energy required to remove an electron from the surface of a metal. As the atomic size increases down a group,the ionization energy decreases,meaning the work function also decreases.$Li$,$Na$,$K$,and $Rb$ belong to Group $1$ of the periodic table.The order of their atomic sizes is $Li Therefore,the order of their work functions is $Li > Na > K > Rb$.Given values: $Li = 2.41 \ eV$,$Na = 2.30 \ eV$,and $Rb = 2.09 \ eV$.The work function of $K$ must lie between $Na$ $(2.30 \ eV)$ and $Rb$ $(2.09 \ eV)$.Among the given options,$2.20 \ eV$ is the only value that falls within the range $2.09 \ eV < K < 2.30 \ eV$.

Element	$A, B, C$
$IE_1$	$400, 550, 1150$
$IE_2$	$2650, 1070, 2090$

In the photoelectric effect,if the work functions of $Li$,$Na$,and $Rb$ are $2.41 \ eV$,$2.30 \ eV$,and $2.09 \ eV$ respectively,the work function of $K$ could approximately be in $eV$?

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