The correct order for wavelengths of absorpti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The complexes are $I: [Ni(H_2O)_6]^{2+}$,$II: [Ni(NH_3)_6]^{2+}$,and $III: [Ni(NO_2)_6]^{4-}$.According to the spectrochemical series,the field st

Vedclass · Accepted Answer

$[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$

Vedclass · Answer

(B) The complexes are $I: [Ni(H_2O)_6]^{2+}$,$II: [Ni(NH_3)_6]^{2+}$,and $III: [Ni(NO_2)_6]^{4-}$.According to the spectrochemical series,the field strength of the ligands is $H_2O The Crystal Field Splitting Energy $(CFSE)$,denoted as $\Delta_0$,is directly proportional to the field strength of the ligand.Therefore,the order of $CFSE$ is $\Delta_0(I) Since the energy of absorption $E$ is inversely proportional to the wavelength $\lambda$ $(E = \frac{hc}{\lambda})$,the order of wavelengths will be the reverse of the energy order.Thus,the correct order of wavelengths is $\lambda(III) < \lambda(II) < \lambda(I)$,which corresponds to $[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$	$I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$	$II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$	$III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$	$IV$. $0$

The correct order for wavelengths of absorption in the visible region for the following complexes will be

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$

$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$

$C$. $[Mn(H_2O)_6]^{3+}$ $III$. $-0.6$

$D$. $[Fe(H_2O)_6]^{3+}$ $IV$. $0$

The electronic configuration of a metal ion in its complex is $[Ar] 3d^4$. For this metal complex,$\Delta_o < P$ ($P=$ energy required for electron pairing in a single orbital). The distribution of electrons in the complex is:

The metal $d-$orbitals that directly face the ligands in $K_3[Co(CN)_6]$ are:

The transition metal complex with the highest value of crystal field splitting $(\Delta_{0})$ is ........ .

Calculate the Crystal Field Stabilization Energy $(CFSE)$ for a high-spin $d^4$ tetrahedral complex.

Vedclass Test Series

Exam Paper Generator

Online Exam Module