The correct electronic configuration and spin | vedclass

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Question

(B) The atomic number of Gadolinium $(Gd)$ is $Z = 64$.Its ground state electronic configuration is $[Xe] 4f^7 5d^1 6s^2$.For the $Gd^{3+}$ ion,three

Vedclass · Accepted Answer

$[Xe] 4f^7$ and $7.9$

Vedclass · Answer

(B) The atomic number of Gadolinium $(Gd)$ is $Z = 64$.Its ground state electronic configuration is $[Xe] 4f^7 5d^1 6s^2$.For the $Gd^{3+}$ ion,three electrons are removed (one from $5d$ and two from $6s$):$Gd^{3+} = [Xe] 4f^7$.Here,there are $7$ unpaired electrons $(n = 7)$ in the $4f$ orbital.The formula for the spin-only magnetic moment $(\mu)$ is $\mu = \sqrt{n(n+2)} \ B.M.$$\mu = \sqrt{7(7+2)} = \sqrt{7 	imes 9} = \sqrt{63} \approx 7.9 \ B.M.$Therefore,the correct option is $B$.

The correct electronic configuration and spin-only magnetic moment $(B.M.)$ of $Gd^{3+}$ $(Z = 64)$ are respectively:

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