What is the number of unpaired electrons in f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic number of lutetium $(Lu)$ is $71$. The electronic configuration of neutral $Lu$ is $[Xe] 4f^{14} 5d^1 6s^2$. In its $+3$ oxidation stat

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The atomic number of lutetium $(Lu)$ is $71$. The electronic configuration of neutral $Lu$ is $[Xe] 4f^{14} 5d^1 6s^2$. In its $+3$ oxidation state,$Lu$ loses three electrons (two from $6s$ and one from $5d$),resulting in the configuration $[Xe] 4f^{14}$. Since the $4f$ subshell is completely filled with $14$ electrons,there are no unpaired electrons in the $f$ orbitals. Therefore,the number of unpaired electrons is $0$.

What is the number of unpaired electrons in $f$ orbitals of lutetium in its $+3$ oxidation state?

Similar Questions

Why are the $E^{\circ}$ values for $Mn^{2+}$,$Ni^{2+}$,and $Zn^{2+}$ more negative than expected?

$A$ substance which is not paramagnetic is

Misch metal is an alloy of $:-$

The catalytic activity of transition metals and their compounds is due to their

Identify the pair of elements in which the number of electrons in the $(n-1)$ shell is the same.

Vedclass Test Series

Exam Paper Generator

Online Exam Module