The correct combination is
- A$[NiCl_4]^{2-} -$ square-planar; $[Ni(CN)_4]^{2-} -$ paramagnetic
- B$[Ni(CN)_4]^{2-} -$ tetrahedral; $[Ni(CO)_4] -$ paramagnetic
- C$[NiCl_4]^{2-} -$ paramagnetic; $[Ni(CO)_4] -$ tetrahedral
- D$[NiCl_4]^{2-} -$ diamagnetic; $[Ni(CO)_4] -$ square-planar
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Similar Questions
What is not correct about $[Fe(H_2O)_5NO]^{2+}$?
Difficult
View SolutionConsider the transition metal ions $Mn^{3+}$,$Cr^{3+}$,$Fe^{3+}$,and $Co^{3+}$. All form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$-orbitals of the complexes is:
DifficultJEE MAIN 2026
View SolutionThe structure of iron pentacarbonyl,$Fe(CO)_5$,is ................. .
Difficult
View SolutionThe number of paramagnetic complexes among $[FeF_6]^{3-}, [Fe(CN)_6]^{3-}, [Mn(CN)_6]^{3-}, [Co(C_2O_4)_3]^{3-}, [MnCl_6]^{3-}$,and $[CoF_6]^{3-}$ that involve $d^2sp^3$ hybridization is ....................
Assertion : $[FeF_6]^{3-}$ is a low spin complex.
Reason : Low spin complexes have a lesser number of unpaired electrons.
Reason : Low spin complexes have a lesser number of unpaired electrons.
MediumAIIMS 2013
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