The correct arrangement of the species in the | vedclass

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(D) We know that $	ext{Bond order} \propto \frac{1}{	ext{Bond length}}$.$CO$ molecule has a bond order of $3$ $(C\equiv O)$.$CO_{2}$ molecule has a

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$CO_{3}^{2-}, HCO_{2}^{-}, CO_{2}, CO$

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(D) We know that $	ext{Bond order} \propto \frac{1}{	ext{Bond length}}$.$CO$ molecule has a bond order of $3$ $(C\equiv O)$.$CO_{2}$ molecule has a bond order of $2$ $(O=C=O)$.$HCO_{2}^{-}$ (formate ion) has a resonance hybrid with a bond order of $1.5$.$CO_{3}^{2-}$ (carbonate ion) has a resonance hybrid with a bond order of $1.33$.Since bond order is inversely proportional to bond length,the decreasing order of bond length is: $CO_{3}^{2-} (1.33) > HCO_{2}^{-} (1.5) > CO_{2} (2) > CO (3)$.

The correct arrangement of the species in the decreasing order of the bond length between carbon and oxygen in them is

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