The coordinates of centre of mass of a unifor | vedclass

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Question

$\mathrm{m}_{1}=3 \mathrm{kg}$

$\mathrm{m}_{2}=1 \mathrm{kg}$

Mass of plate- 1 is assumed to be concentrated at $(0.5,1.5)$

Mass of plate- 2

Vedclass · Accepted Answer

$(0.75\; \mathrm{m}, 1.75\; \mathrm{m})$

Vedclass · Answer

$\mathrm{m}_{1}=3 \mathrm{kg}$

$\mathrm{m}_{2}=1 \mathrm{kg}$

Mass of plate- 1 is assumed to be concentrated at $(0.5,1.5)$

Mass of plate- 2 is assumed to be concentrated at $(1.5,2.5)$

$\mathrm{x}_{\mathrm{cm}}=\frac{\mathrm{m}_{1} \mathrm{x}_{1}+\mathrm{m}_{2} \mathrm{x}_{2}}{\mathrm{m}_{1}+\mathrm{m}_{2}}=\frac{3 	imes 0.5+1 	imes 1.5}{4}=0.75$

$\mathrm{y}_{\mathrm{cm}}=\frac{\mathrm{m}_{1} \mathrm{y}_{1}+\mathrm{m}_{2} \mathrm{y}_{2}}{\mathrm{m}_{1}+\mathrm{m}_{2}}=\frac{3 	imes 1.5+1 	imes 2.5}{4}=1.75$

The coordinates of centre of mass of a uniform flag shaped lamina (thin flat plate) of mass $4\;kg$. (The coordinates of the same are shown in figure) are

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