The conductivity of $0.20 \ M \ KCl$ solution at $300 \ K$ is $0.0248 \ \Omega^{-1} \ cm^{-1}$. What is its molar conductivity?

  • A
    $124 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
  • B
    $93 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
  • C
    $62 \ \Omega^{-1} \ cm^2 \ mol^{-1}$
  • D
    $186 \ \Omega^{-1} \ cm^2 \ mol^{-1}$

Explore More

Similar Questions

Conductivity of a solution is $1.26 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$. Calculate molar conductivity for $0.01 \ M$ solution.

$A$ conductivity cell containing $5 \times 10^{-4} \ M \ NaCl$ solution develops a resistance of $14000 \ \Omega$ at $25^{\circ} C$. Calculate the conductivity of the solution if the cell constant is $0.84 \ cm^{-1}$.

At a particular temperature,the ratio of molar conductance to specific conductance of $0.01 \ M$ $NaCl$ solution is

Resistance of $0.1\, M\, KCl$ solution in a conductance cell is $300\, \Omega$ and conductivity is $0.013\, S\, cm^{-1}$. The value of cell constant is

The specific conductivity of a saturated solution of silver chloride is $2 \times 10^{-6} \, S \, cm^{-1}$ at $25 \, ^oC$. What will be the solubility of silver chloride at $25 \, ^oC$ if molar conductivities at infinite dilution of $Ag^{+}$ and $Cl^{-}$ ions are $60$ and $80 \, S \, cm^2 \, mol^{-1}$ respectively?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo