At a particular temperature,the ratio of molar conductance to specific conductance of $0.01 \ M$ $NaCl$ solution is
- A$10^{5} \ cm^{3} \ mol^{-1}$
- B$10^{3} \ cm^{3} \ mol^{-1}$
- C$10 \ cm^{3} \ mol^{-1}$
- D$10^{5} \ cm^{2} \ mol^{-1}$
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Similar Questions
Calculate the molar conductivity of a solution having a concentration of $0.08 \ M$ and a resistivity of $5 \times 10^{-3} \ \Omega \ cm$.
Medium
View SolutionCalculate $\wedge_0$ of $CH_2ClCOOH$ if $\wedge_0$ for $HCl, KCl$ and $CH_2ClCOOK$ are $4.2, 1.5$ and $1.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.
$\Lambda_{m}^0$ for $NaCl$,$HCl$ and $NaAc$ are $126.4 \ S \ cm^2 \ mol^{-1}$,$425.9 \ S \ cm^2 \ mol^{-1}$ and $91.0 \ S \ cm^2 \ mol^{-1}$ respectively. Calculate $\Lambda^0$ for $HAc$.
The dissociation constant of acetic acid is $1.75 \times 10^{-5}$ and $\Lambda _{CH_3COOH}^o = 370.6 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acetic acid solution will be:
Difficult
View Solution$\wedge _m^o$ for $NaCl$,$HCl$ and $NaA$ are $126.4$,$425.9$ and $100.5 \ S \ cm^2 \ mol^{-1}$,respectively. If the conductivity of $0.001 \ M \ HA$ is $5 \times 10^{-5} \ S \ cm^{-1}$,degree of dissociation of $HA$ is
DifficultJEE MAIN 2019
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