The compressibility of water is 6 times 10^{- | vedclass

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(C) The compressibility $K$ is defined as the reciprocal of the Bulk modulus $B$, given by $K = \frac{1}{B} = -\frac{\Delta V}{P V}$.Here, the negativ

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$24$

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(C) The compressibility $K$ is defined as the reciprocal of the Bulk modulus $B$, given by $K = \frac{1}{B} = -\frac{\Delta V}{P V}$.Here, the negative sign indicates that an increase in pressure leads to a decrease in volume.Given:Compressibility $K = 6 	imes 10^{-10} \,m^{2}/N$Initial volume $V = 1 \,L = 10^{-3} \,m^{3}$Pressure change $P = 4 	imes 10^{7} \,N/m^{2}$The decrease in volume $\Delta V$ is given by:$\Delta V = K \cdot P \cdot V$$\Delta V = (6 	imes 10^{-10} \,m^{2}/N) 	imes (4 	imes 10^{7} \,N/m^{2}) 	imes (10^{-3} \,m^{3})$$\Delta V = 24 	imes 10^{-6} \,m^{3}$Since $1 \,m^{3} = 10^{3} \,L = 10^{6} \,mL$, we convert the volume change to millilitres:$\Delta V = 24 	imes 10^{-6} 	imes 10^{6} \,mL = 24 \,mL$.

The compressibility of water is $6 \times 10^{-10} \,m^{2}/N$. If one litre of water is subjected to a pressure of $4 \times 10^{7} \,N/m^{2}$, then the decrease in its volume in millilitre will be

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