How much should the pressure on a litre of water be changed to compress it by $0.10\%?$

The volume of a material reduces by $2 \%$ when the pressure is increased from $1 \text{ atm}$ to $2 \text{ atm}$. What is its bulk modulus?

An object is located at $2 \, km$ beneath the surface of the water. If the fractional compression $\frac{\Delta V}{V}$ is $1.36 \, \%$,the ratio of hydraulic stress to the corresponding hydraulic strain will be ......... . [Given: density of water is $1000 \, kg \, m^{-3}$ and $g = 9.8 \, m \, s^{-2}$.]

$A$ cubical solid aluminium (bulk modulus $B = -V \frac{dP}{dV} = 70 \text{ GPa}$) block has an edge length of $1 \text{ m}$ on the surface of the earth. It is kept on the floor of a $5 \text{ km}$ deep ocean. Taking the average density of water $\rho = 10^3 \text{ kg m}^{-3}$ and the acceleration due to gravity $g = 10 \text{ m s}^{-2}$,the change in the edge length of the block in $\text{mm}$ is . . . . .

$A$ solid sphere of radius $r$ made of a soft material of bulk modulus $K$ is surrounded by a liquid in a cylindrical container. $A$ massless piston of area $a$ floats on the surface of the liquid,covering the entire cross-section of the cylindrical container. When a mass $m$ is placed on the surface of the piston to compress the liquid,the fractional decrement in the radius of the sphere,$\left( \frac{dr}{r} \right)$ is:

$A$ rubber ball is taken into the deep sea such that its volume decreases by $x \%$. The bulk modulus of rubber is $K$ and the density of sea water is $\rho$. The depth $h$ to which the rubber ball is taken is proportional to $(g = \text{acceleration due to gravity})$: