The compounds that produce CO_2 with aqueous | vedclass

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(C) Compounds that are stronger acids than carbonic acid $(H_2CO_3)$ react with aqueous $NaHCO_3$ to evolve $CO_2$ gas.$A$. Benzoic acid $(pK_a \appro

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$A, C$ and $D$ only

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(C) Compounds that are stronger acids than carbonic acid $(H_2CO_3)$ react with aqueous $NaHCO_3$ to evolve $CO_2$ gas.$A$. Benzoic acid $(pK_a \approx 4.2)$ is stronger than $H_2CO_3$ $(pK_a \approx 6.35)$.$C$. $2,4,6$-Trinitrophenol (Picric acid) $(pK_a \approx 0.38)$ is a very strong acid,much stronger than $H_2CO_3$.$D$. Cyclohexanecarboxylic acid $(pK_a \approx 4.9)$ is stronger than $H_2CO_3$.Phenol $(B)$ and $4$-Methoxyphenol $(E)$ are weaker acids than $H_2CO_3$ and do not react with $NaHCO_3$ to evolve $CO_2$.Therefore,compounds $A, C,$ and $D$ produce $CO_2$ with aqueous $NaHCO_3$ solution.

The compounds that produce $CO_2$ with aqueous $NaHCO_3$ solution are:
$A$. Benzoic acid
$B$. Phenol
$C$. $2,4,6$-Trinitrophenol (Picric acid)
$D$. Cyclohexanecarboxylic acid
$E$. $4$-Methoxyphenol
Choose the correct answer from the options given below:

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The compounds that produce $CO_2$ with aqueous $NaHCO_3$ solution are: $A$. Benzoic acid$B$. Phenol$C$. $2,4,6$-Trinitrophenol (Picric acid)$D$. Cyclohexanecarboxylic acid$E$. $4$-MethoxyphenolChoose the correct answer from the options given below: