The reaction of RCOOH with R'OH takes place i | vedclass

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(A) The esterification reaction (Fischer esterification) proceeds via the nucleophilic acyl substitution mechanism.$1$. The carbonyl oxygen of the car

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(A) The esterification reaction (Fischer esterification) proceeds via the nucleophilic acyl substitution mechanism.$1$. The carbonyl oxygen of the carboxylic acid is protonated by $H_2SO_4$,making the carbonyl carbon more electrophilic.$2$. The alcohol $(R'OH)$ acts as a nucleophile and attacks the electrophilic carbonyl carbon,forming a tetrahedral intermediate.$3$. The structure of this tetrahedral intermediate is $R-C(OH)_2-OR'$,where the oxygen atom derived from the alcohol is protonated (bearing a positive charge).$4$. Comparing the given options with the mechanism,the structure corresponding to the tetrahedral intermediate is represented in option $A$.

The reaction of $RCOOH$ with $R'OH$ takes place in the presence of $H_2SO_4$ to form an ester. The intermediate in the reaction is:

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