The compound interest on ₹ 1,800 at 10 % per | vedclass

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(B) Given:Principal $(P) = ₹ 1800$Rate $(R) = 10 \% 	ext{ per annum}$Compound Interest $(C.I.) = ₹ 378$Let the time be $T$ years.The formula for Comp

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(B) Given:Principal $(P) = ₹ 1800$Rate $(R) = 10 \% 	ext{ per annum}$Compound Interest $(C.I.) = ₹ 378$Let the time be $T$ years.The formula for Compound Interest is:$C.I. = P \left(1 + \frac{R}{100}ight)^T - P$Substituting the given values:$378 = 1800 \left(1 + \frac{10}{100}ight)^T - 1800$$378 + 1800 = 1800 (1.1)^T$$2178 = 1800 (1.1)^T$$(1.1)^T = \frac{2178}{1800}$$(1.1)^T = 1.21$Since $(1.1)^2 = 1.21$,we have $T = 2$.Therefore,the time is $2$ years.

The compound interest on $₹ 1,800$ at $10 \%$ per annum for a certain period of time is $₹ 378$. Find the time in years.

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