The compound interest (In ₹) on ₹ 12000 for 9 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) Here, $P=12000, R=20$ and $t=\frac{9}{12}$

$	herefore \quad CI =P\left[\left(1+\frac{R}{100 	imes 4}ight)^{4 	imes t}-1ight]$

$=12000

Vedclass · Accepted Answer

$1891.50$

Vedclass · Answer

(a) Here, $P=12000, R=20$ and $t=\frac{9}{12}$

$	herefore \quad CI =P\left[\left(1+\frac{R}{100 	imes 4}ight)^{4 	imes t}-1ight]$

$=12000\left[\left(1+\frac{20}{100 	imes 4}ight)^{4 	imes \frac{9}{12}}-1ight]$

$=12000\left[\left(1+\frac{1}{20}ight)^{3}-1ight]=\frac{12000 	imes 1261}{20 	imes 20 	imes 20}$

$=₹ 1891.50$

The compound interest (In ₹) on ₹ $12000$ for $9$ months at $20 \%$ per annum, interest being compounded quarterly, is

Similar Questions

What is the difference between the compound interests (In ₹ ) on ₹ $5000$ for $1 \frac{1}{2}$ years at $4 \%$ per annum compounded yearly end half-yearly?

What sum of money (In ₹) at compound interest will amount to ₹ $650$ at the end of the first year and ₹ $676$ at the end of the second year?

A sum of money doubles in $3$ years at compound interest, compounded annually. It will become $4$ times of itself in

The difference between simple interest and compound interest compounded annually on a certain sum of money for $2$ years at $4 \%$ per annum is ₹ $1 .$ The sum (in ₹) is

If the difference of the compound interest on a sum of money for $3$ years is ₹ $186 .$ Find the sum of money (In ₹) if the rate of interest in both cases be $10 \%$