The compound formed by the reaction of ethana | vedclass

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(C) The reaction between ethanal $(CH_3CHO)$ and semicarbazide $(NH_2NHCONH_2)$ is a nucleophilic addition-elimination reaction.The reaction is as fol

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$3$

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(C) The reaction between ethanal $(CH_3CHO)$ and semicarbazide $(NH_2NHCONH_2)$ is a nucleophilic addition-elimination reaction.The reaction is as follows:$CH_3CHO + NH_2NHCONH_2 \rightarrow CH_3CH=NNHCONH_2 + H_2O$In the product,ethanal semicarbazone $(CH_3CH=NNHCONH_2)$,we can count the nitrogen atoms:There is one $N$ atom in the $C=N$ group,one $N$ atom in the $NH$ group,and one $N$ atom in the $NH_2$ group.Total number of nitrogen atoms = $1 + 1 + 1 = 3$.

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

The compound formed by the reaction of ethanal with semicarbazide contains $.....................$ number of nitrogen atoms.

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