The compound (X) in the given reaction is:MeO | vedclass

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(C) The given reaction is an example of the Perkin reaction.In the Perkin reaction,an aromatic aldehyde reacts with an acid anhydride (in the presence

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$(CH_3CO)_2O$

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(C) The given reaction is an example of the Perkin reaction.In the Perkin reaction,an aromatic aldehyde reacts with an acid anhydride (in the presence of the corresponding sodium salt of the acid) to form an $\alpha,\beta$-unsaturated carboxylic acid.Here,$p$-methoxybenzaldehyde reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of sodium acetate $(CH_3COONa)$ to yield $p$-methoxycinnamic acid.Therefore,$(X)$ is acetic anhydride,which is $(CH_3CO)_2O$.

The compound $(X)$ in the given reaction is:
$MeO-C_6H_4-CHO + (X) \xrightarrow{CH_3COONa, H_3O^+} MeO-C_6H_4-CH=CHCOOH$

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The compound $(X)$ in the given reaction is:$MeO-C_6H_4-CHO + (X) \xrightarrow{CH_3COONa, H_3O^+} MeO-C_6H_4-CH=CHCOOH$