The complex ion having minimum magnitude of D | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnitude of $\Delta_{0}$ depends on the nature of the ligand and the oxidation state of the central metal ion.According to the spectrochemica

Vedclass · Accepted Answer

$[Co(Cl)_{6}]^{3-}$

Vedclass · Answer

(C) The magnitude of $\Delta_{0}$ depends on the nature of the ligand and the oxidation state of the central metal ion.According to the spectrochemical series,the field strength of the ligands is $Cl^{-} Ligands with lower field strength result in a smaller crystal field splitting energy $(\Delta_{0})$.Since $Cl^{-}$ is the weakest field ligand among the given options,the complex $[Co(Cl)_{6}]^{3-}$ will have the minimum magnitude of $\Delta_{0}$.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Ti(H_2O)_6]^{2+}$	$I$. $-1.2$
$B$. $[V(H_2O)_6]^{2+}$	$II$. $-0.8$
$C$. $[Mn(H_2O)_6]^{3+}$	$III$. $-0.6$
$D$. $[Fe(H_2O)_6]^{3+}$	$IV$. $0$

The complex ion having minimum magnitude of $\Delta_{0}$ $(CFSE)$ is

Similar Questions

Calculate the Crystal Field Stabilization Energy $(CFSE)$ for a high-spin $d^4$ tetrahedral complex.

The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

Which sets of the $d$-orbitals are directly oriented towards the ligands in octahedral coordination compounds?

Which relationship is correct for the crystal field splitting energy between octahedral $(\Delta_0)$ and tetrahedral $(\Delta_t)$ complexes?

Match List-$I$ with List-$II$:

List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Ti(H_2O)_6]^{2+}$ $I$. $-1.2$

$B$. $[V(H_2O)_6]^{2+}$ $II$. $-0.8$

$C$. $[Mn(H_2O)_6]^{3+}$ $III$. $-0.6$

$D$. $[Fe(H_2O)_6]^{3+}$ $IV$. $0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module