The complete solution of the inequation $x^2 - 4x < 12$ is

  • A
    $x < -2$ or $x > 6$
  • B
    $-6 < x < 2$
  • C
    $2 < x < 6$
  • D
    $-2 < x < 6$

Explore More

Similar Questions

For $0 \leq p \leq 1$ and for any positive $a, b$,let $I(p)=(a+b)^{p}$ and $J(p)=a^{p}+b^{p}$. Then:

The set of all values of $x$ for which the inequalities $x^2-7x+10 \geq 0$ and $2x+3-x^2 > 0$ hold simultaneously is

Let $S$ be the set of positive integral values of $a$ for which $\frac{ax^2+2(a+1)x+9a+4}{x^2-8x+32} < 0, \forall x \in R$. Then,the number of elements in $S$ is:

If $(2k-1)x^2 - 2(3k-2)x + 4k > 0$ for every $x \in R$,then the sum of all possible integral values of $k$ is

If $x^2+2px-2p+8>0$ for all real values of $x$,then the set of all possible values of $p$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo