Class 11MathematicsPair of straight linesBisectors of the angle between the lines, Point of intersection of the lines
DifficultThe combined equation of the two lines $ax+by+c=0$ and $a'x+b'y+c'=0$ can be written as $(ax+by+c)(a'x+b'y+c')=0$. The equation of the angle bisectors of the lines represented by the equation $2x^2+xy-3y^2=0$ is:
- A$3x^2+5xy+2y^2=0$
- B$x^2-y^2+10xy=0$
- C$3x^2+xy-2y^2=0$
- D$x^2-y^2-10xy=0$
Explore More
Similar Questions
If $(-1, -1)$ is the point of intersection of the pair of lines $2x^2 + 5xy - 3y^2 + 2gx + 2fy + c = 0$,then $g + f =$
DifficultTS EAMCET 2025
View SolutionIf the pair of lines $x^2-16pxy-y^2=0$ and $x^2-16qxy-y^2=0$ are such that each pair bisects the angle between the other pair,then $pq=$
If the lines represented by $x^2 - 2pxy - y^2 = 0$ are rotated about the origin by an angle $\theta$ in clockwise and counter-clockwise directions respectively,then the equation of the bisector of the angle between the lines in the new position is:
Difficult
View SolutionLet the equation of the pair of lines,$y=px$ and $y=qx$,be written as $(y-px)(y-qx)=0$. Then the equation of the pair of angle bisectors of the lines $x^{2}-4xy-5y^{2}=0$ is:
The joint equation of the bisectors of the angles between the lines represented by $2x^2 + 11xy + 3y^2 = 0$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo