The coefficient of induction of a choke coil | vedclass

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(B) The power factor of an $LR$ circuit is given by $\cos \phi = \frac{R}{Z}$,where $Z$ is the impedance.$Z = \sqrt{R^2 + X_L^2} = \sqrt{R^2 + (\omega

Vedclass · Accepted Answer

$0.3$

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(B) The power factor of an $LR$ circuit is given by $\cos \phi = \frac{R}{Z}$,where $Z$ is the impedance.$Z = \sqrt{R^2 + X_L^2} = \sqrt{R^2 + (\omega L)^2} = \sqrt{R^2 + (2\pi f L)^2}$.Given: $R = 12\,\Omega$,$L = 0.1\,H$,$f = 60\,Hz$.First,calculate the inductive reactance $X_L = 2\pi f L = 2 	imes 3.14 	imes 60 	imes 0.1 \approx 37.7\,\Omega$.Now,calculate the impedance $Z = \sqrt{12^2 + 37.7^2} = \sqrt{144 + 1421.29} = \sqrt{1565.29} \approx 39.56\,\Omega$.The power factor $\cos \phi = \frac{R}{Z} = \frac{12}{39.56} \approx 0.303$.Rounding to the nearest given option,the power factor is $0.3$.

The coefficient of induction of a choke coil is $0.1\,H$ and resistance is $12\,\Omega$. If it is connected to an alternating current source of frequency $60\,Hz$,then the power factor will be:

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