$A$ circuit,consisting of an inductance and a resistance in series,is connected to a $250 \ V$ $A$.$C$. supply. It draws a current of $10 \ A$. If the power consumed in the circuit is $1500 \ W$,calculate the wattless current. (in $A$)

For the series $LCR$ circuit connected with a $220 \ V$,$50 \ Hz$ a.c. source as shown in the figure,the power factor is $\frac{\alpha}{10}$. The value of $\alpha$ is . . . . . .

$A$ sinusoidal $AC$ current passes through a resistor of resistance $R$ in an $LCR$ series circuit. If the phase difference between the supplied voltage and the supplied current is $\theta$ and the peak value of the supplied current is $I_0$,then the power dissipated in the circuit is:

$A$ lamp consumes only $50\%$ of peak power in an $AC$ circuit. What is the phase difference between the applied voltage and the circuit current?

$A$ coil of inductive reactance $31\,\Omega$ has a resistance of $8\,\Omega$. It is placed in series with a capacitor of capacitive reactance $25\,\Omega$. The combination is connected to an $A$.$C$. source of $110\,V$. The power factor of the circuit is:

In an $AC$ circuit,$V$ and $I$ are given by $V = 150 \sin(150t) \, V$ and $I = 150 \sin(150t + \frac{\pi}{3}) \, A$. The power dissipated in the circuit is $W$.