A circular wire of diameter 10,cm is cut and | vedclass

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(C) The length of the wire is equal to the circumference of the circular wire with diameter $d_1 = 10\,cm$.Length of wire $(l)$ = $\pi 	imes d_1 = 10

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$\frac{\pi}{5}\,	ext{radian}$

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(C) The length of the wire is equal to the circumference of the circular wire with diameter $d_1 = 10\,cm$.Length of wire $(l)$ = $\pi 	imes d_1 = 10\pi\,cm$.The wire is placed along the circumference of a circle with diameter $d_2 = 1\,m = 100\,cm$.The radius of this circle $(r)$ = $\frac{d_2}{2} = \frac{100}{2} = 50\,cm$.The angle $(	heta)$ subtended by an arc of length $l$ at the centre of a circle of radius $r$ is given by $	heta = \frac{l}{r}$.Substituting the values,$	heta = \frac{10\pi}{50} = \frac{\pi}{5}\,	ext{radian}$.

$A$ circular wire of diameter $10\,cm$ is cut and placed along the circumference of a circle of diameter $1\,m$. The angle subtended by the wire at the centre of the circle is equal to

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