The charge on 500,cc of water due to protons | vedclass

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(B) The density of water is $1\,g/cc$,so the mass of $500\,cc$ of water is $500\,g$.The molar mass of water $(H_2O)$ is $18\,g/mol$.The number of mole

Vedclass · Accepted Answer

$2.67 	imes 10^7\,C$

Vedclass · Answer

(B) The density of water is $1\,g/cc$,so the mass of $500\,cc$ of water is $500\,g$.The molar mass of water $(H_2O)$ is $18\,g/mol$.The number of moles of water is $n_{moles} = \frac{500}{18} \approx 27.78\,mol$.Each molecule of water $(H_2O)$ contains $10$ protons ($1$ from each $H$ atom and $8$ from the $O$ atom).The total number of protons $N_p$ is given by $N_p = n_{moles} 	imes N_A 	imes 10$,where $N_A = 6.022 	imes 10^{23}\,mol^{-1}$.$N_p = \frac{500}{18} 	imes 6.022 	imes 10^{23} 	imes 10 \approx 1.673 	imes 10^{26}$.The total charge $Q$ is $N_p 	imes e$,where $e = 1.6 	imes 10^{-19}\,C$.$Q = 1.673 	imes 10^{26} 	imes 1.6 	imes 10^{-19} \approx 2.67 	imes 10^7\,C$.

The charge on $500\,cc$ of water due to protons will be

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