The charge on 500,cc of water due to protons | vedclass

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Question

(b) $Q = ne$; where $n$ = number of moles $&times; 6.02 &times; 10^{23}&times; 10$
$==>$ $Q = \frac{{500}}{{18}} 	imes 6.02 	imes {10^{23}} 	im

Vedclass · Accepted Answer

$2.67 	imes {10^7}\,C$

Vedclass · Answer

(b) $Q = ne$; where $n$ = number of moles $&times; 6.02 &times; 10^{23}&times; 10$
$==>$ $Q = \frac{{500}}{{18}} 	imes 6.02 	imes {10^{23}} 	imes 10 	imes 1.6 	imes {10^{ - 19}} = 2.67 	imes {10^7}\,C$

The charge on $500\,cc$ of water due to protons will be

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