The centre of gravity of a body on the earth coincides with its centre of mass for a small object,whereas for an extended object,it may not. What is the qualitative meaning of 'small' and 'extended' in this regard? For which of the following does the centre of gravity coincide with the centre of mass: a building,a pond,a lake,a mountain?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The qualitative meaning of 'small' and 'extended' depends on the variation of the acceleration due to gravity $(g)$ over the dimensions of the object.
If the vertical height or dimensions of the object are very small compared to the radius of the earth $(R_e \approx 6400 \ km)$,the gravitational field is considered uniform,and the object is called 'small'. In this case,the centre of gravity coincides with the centre of mass.
If the dimensions of the object are large enough that the variation in $g$ becomes significant,the object is called 'extended'. In this case,the centre of gravity may not coincide with the centre of mass.
$(1)$ $A$ building and a pond are considered 'small' objects because their vertical extent is negligible compared to $R_e$. Thus,for these,the centre of gravity coincides with the centre of mass.
$(2)$ $A$ deep lake and a mountain are examples of 'extended' objects because their vertical extent is significant enough that the variation in $g$ cannot be ignored. Thus,for these,the centre of gravity may not coincide with the centre of mass.

Explore More

Similar Questions

If the radius of the Earth shrinks by $1.5 \%$ (mass remaining same),then the value of gravitational acceleration changes by ......... $\%$

Difficult
View Solution

The magnitudes of the gravitational force at distances $r_1$ and $r_2$ from the centre of a uniform sphere of radius $R$ and mass $M$ are $F_1$ and $F_2$ respectively. Then

Assuming the earth to be a sphere of uniform density,the acceleration due to gravity inside the earth at a distance of $r$ from the centre is proportional to

Assume there are two identical simple pendulum clocks. Clock-$1$ is placed on the Earth and Clock-$2$ is placed on a space station located at a height $h$ above the Earth's surface. Clock-$1$ and Clock-$2$ operate with time periods of $4\,s$ and $6\,s$ respectively. Then the value of $h$ is $....\,km$ (consider the radius of the Earth $R_E = 6400\,km$ and $g$ on Earth $10\,m/s^2$).

Considering Earth to be a sphere of radius $R$ having uniform density $\rho$,the value of acceleration due to gravity $g$ in terms of $R$,$\rho$,and $G$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo