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(B) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the oxidation state of iron is calculated by considering the ligands.Water $(H_2O)$ is a neutral li

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$1$

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(B) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the oxidation state of iron is calculated by considering the ligands.Water $(H_2O)$ is a neutral ligand with a charge of $0$.The nitric oxide $(NO)$ ligand in this specific complex acts as $NO^+$.The sulfate ion $(SO_4^{2-})$ has a charge of $-2$.Let the oxidation state of $Fe$ be $x$.$x + 5(0) + 1(+1) + (-2) = 0$$x + 1 - 2 = 0$$x - 1 = 0$$x = +1$.Therefore,the oxidation state of iron is $+1$.

The brown ring complex compound is formulated as $[Fe(H_2O)_5NO]SO_4$. The oxidation state of iron is

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