(A) Let the oxidation state of $Fe$ be $x$.In $K_4[Fe(CN)_6]$,the oxidation state of $K$ is $+1$ and the oxidation state of $CN^-$ is $-1$.Setting the

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(A) Let the oxidation state of $Fe$ be $x$.In $K_4[Fe(CN)_6]$,the oxidation state of $K$ is $+1$ and the oxidation state of $CN^-$ is $-1$.Setting the sum of oxidation states to zero:$4 \times (+1) + x + 6 \times (-1) = 0$$4 + x - 6 = 0$$x - 2 = 0$$x = +2$Therefore,the oxidation state of $Fe$ is $+2$.