The Boolean expression $\sim(p \vee q) \vee (\sim p \wedge q)$ is equivalent to:

  • A
    $p$
  • B
    $q$
  • C
    $\sim q$
  • D
    $\sim p$

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If the truth value of the expression $[(p \vee q) \wedge (q$ $\rightarrow r) \wedge (\sim r)]$ $\rightarrow (p \wedge q)$ is False,then the truth values of $p, q, r$ are respectively:

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The proposition $p \Rightarrow \sim (p \wedge \sim q)$ is

The statement $[p \wedge (q \vee r)] \vee [\sim r \wedge \sim q \wedge p]$ is equivalent to

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