The bond order of NO molecule is | vedclass

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Question

(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of bonding }}{e^ - } - {\rm{ No}}{\rm{. of antibonding }}{e^ - }}}{2}$ $ = \frac{{8 - 3}}{2} =

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$2.5$

Vedclass · Answer

(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of bonding }}{e^ - } - {\rm{ No}}{\rm{. of antibonding }}{e^ - }}}{2}$ $ = \frac{{8 - 3}}{2} = \frac{5}{2} = 2.5$.

The bond order of $NO$ molecule is

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