The bond dissociation energy $(E)$ and bond length $(R)$ of $O_2$,$N_2$,and $F_2$ follow the order as:
- A$E(N_2) > E(O_2) > E(F_2)$ and $R(N_2) > R(O_2) > R(F_2)$
- B$E(F_2) > E(O_2) > E(N_2)$ and $R(F_2) > R(O_2) > R(N_2)$
- C$E(N_2) > E(O_2) > E(F_2)$ and $R(F_2) > R(O_2) > R(N_2)$
- D$E(O_2) > E(N_2) > E(F_2)$ and $R(F_2) > R(N_2) > R(O_2)$
Explore More
Similar Questions
The correct order of energy of $\sigma_{2p_z}$,$\pi_{2p_x}$,$\pi_{2p_y}$,$\pi_{2p_x}^*$,$\pi_{2p_y}^*$ and $\sigma_{2p_z}^*$ orbitals in $F_2$ is:
Explain in short: $MO$ occupancy and molecular properties for $B_2, C_2, N_2, O_2, F_2, Ne_2$.
Using $MOT$,compare $O_{2}^{+}$ and $O_{2}^{-}$ species and choose the incorrect option.
According to the Molecular Orbital Theory,which of the following properties does the $O_2^+$ species possess?
Difficult
View SolutionThe $H.O.M.O.$ (Highest Occupied Molecular Orbital) of the $CO$ molecule is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo