The bond order in O_2^+ is | vedclass

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(B) The total number of electrons in $O_2^+$ is $16 - 1 = 15$. According to Molecular Orbital Theory,the electronic configuration of $O_2^+$ is: $\sig

Vedclass · Accepted Answer

$2.5$

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(B) The total number of electrons in $O_2^+$ is $16 - 1 = 15$. According to Molecular Orbital Theory,the electronic configuration of $O_2^+$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. Number of bonding electrons $(N_b)$ = $10$. Number of antibonding electrons $(N_a)$ = $5$. Bond Order = $\frac{N_b - N_a}{2} = \frac{10 - 5}{2} = \frac{5}{2} = 2.5$.

The bond order in $O_2^+$ is

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