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(C) According to Gauss's Law,the net electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$,where $q_{encl

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For $I$ and $II$ cases

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(C) According to Gauss's Law,the net electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$,where $q_{enclosed}$ is the net charge enclosed by the surface.If no charge is enclosed by the surface $(q_{enclosed} = 0)$,the net flux through the surface is zero.In cases $I$ and $II$,the point charge is enclosed within the closed surface,so the net flux is non-zero.In cases $III$ and $IV$,the point charge is outside the closed surface,so the net charge enclosed is zero,which means the net flux through these surfaces is zero.Therefore,the net flux is non-zero only for cases $I$ and $II$.

The black shapes in the figure below are closed surfaces. The electric field lines are shown by dashed arrows. For which case,the net flux through the surfaces is non-zero?

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