The binding energy of deuteron is 2.2 , MeV a | vedclass

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(C) The nuclear fusion reaction is given by: $_{1}^{2}H + _{1}^{2}H \rightarrow _{2}^{4}He + Q$.The energy released $(Q)$ in a nuclear reaction is equ

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$23.6$

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(C) The nuclear fusion reaction is given by: $_{1}^{2}H + _{1}^{2}H ightarrow _{2}^{4}He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = B.E.(_{2}^{4}He) - 2 	imes B.E.(_{1}^{2}H)$.Given:$B.E.(_{2}^{4}He) = 28 \, MeV$$B.E.(_{1}^{2}H) = 2.2 \, MeV$Substituting the values:$Q = 28 - 2(2.2) \, MeV$$Q = 28 - 4.4 \, MeV$$Q = 23.6 \, MeV$.Therefore,the energy released is $23.6 \, MeV$.

The binding energy of deuteron is $2.2 \, MeV$ and that of $_2^4He$ is $28 \, MeV$. If two deuterons are fused to form one $_2^4He$,then the energy released is ......... $MeV$.

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