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(B) Given,energy released per nucleus fission,$E_0 = 188 MeV$ and mass,$m = 100 g$.First,calculate the number of nuclei $N$ in $100 g$ of ${ }_{92} U^

Vedclass · Accepted Answer

$7.71 	imes 10^{12} J$

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(B) Given,energy released per nucleus fission,$E_0 = 188 MeV$ and mass,$m = 100 g$.First,calculate the number of nuclei $N$ in $100 g$ of ${ }_{92} U^{235}$:$N = \frac{m}{M} 	imes N_A = \frac{100}{235} 	imes 6.022 	imes 10^{23} \approx 2.56 	imes 10^{23}$ nuclei.Next,convert the energy released per nucleus into Joules:$E_0' = 188 	imes 10^6 	imes 1.6 	imes 10^{-19} J = 300.8 	imes 10^{-13} J$.The total energy released $E$ for $N$ nuclei is:$E = N 	imes E_0' = (2.56 	imes 10^{23}) 	imes (300.8 	imes 10^{-13} J) \approx 7.71 	imes 10^{12} J$.Thus,the correct option is $B$.

The energy released when one nucleus of ${ }_{92} U^{235}$ undergoes fission is $188 MeV$. The energy released when $100 g$ of ${ }_{92} U^{235}$ undergoes fission is:

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