The batting average for 40 innings of a crick | vedclass

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Question

(D) Let the cricketer's highest score $= x$ runs.Therefore,the minimum score $= (x - 172)$ runs.Total runs scored in $40$ innings $= 40 	imes 50 = 20

Vedclass · Accepted Answer

$174$

Vedclass · Answer

(D) Let the cricketer's highest score $= x$ runs.Therefore,the minimum score $= (x - 172)$ runs.Total runs scored in $40$ innings $= 40 	imes 50 = 2000$ runs.Total runs scored in $38$ innings $= 38 	imes 48 = 1824$ runs.The sum of the highest and lowest scores is the difference between the total runs of $40$ innings and $38$ innings:$x + (x - 172) = 2000 - 1824$$2x - 172 = 176$$2x = 176 + 172$$2x = 348$$x = 174$Thus,the highest score of the player is $174$ runs.

The batting average for $40$ innings of a cricketer is $50$ runs. His highest score exceeds his lowest score by $172$ runs. If these two innings are excluded,the average of the remaining $38$ innings is $48$ runs. The highest score of the player is

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