The batting aterage for 40 innings of a crick | vedclass

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Question

Let the cricketer's highest score $=x$ runs

$	herefore$ Minimum score $=(x-172)$ runs

$	herefore$ Total runs scored in 40 innings $=40 	i

Vedclass · Accepted Answer

$174$

Vedclass · Answer

Let the cricketer's highest score $=x$ runs

$	herefore$ Minimum score $=(x-172)$ runs

$	herefore$ Total runs scored in 40 innings $=40 	imes 50=2000$ runs

Total runs scored in $38$ innings $=38 	imes 48=1824$ runs Now, according to the question, $x+x-172=2000-1824=176$

$\Rightarrow 2 x=176+172=348$

$	herefore \quad x=\frac{348}{2}=174$

The batting aterage for $40$ innings of a cricketer is $50$ nuns. His highest score exceeds his lowest score by $172$ runs. If these two innings are excluded, the average of the remaining $38$ innings is $48$ runs. The highest score of the player is

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