The base of a cone with radius 5 , cm and hei | vedclass

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(B) Radius of the cone $=$ radius of the hemisphere $= r = 5 \, cm$.Height of the cone $= h = 12 \, cm$.The slant height of the cone is given by $l =

Vedclass · Accepted Answer

$361.1$

Vedclass · Answer

(B) Radius of the cone $=$ radius of the hemisphere $= r = 5 \, cm$.Height of the cone $= h = 12 \, cm$.The slant height of the cone is given by $l = \sqrt{r^2 + h^2}$.$l = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \, cm$.The total surface area of the article is the sum of the curved surface area of the cone and the curved surface area of the hemisphere.Total Surface Area $= \pi rl + 2\pi r^2 = \pi r(l + 2r)$.Substituting the values: $3.14 	imes 5 	imes (13 + 2 	imes 5) = 3.14 	imes 5 	imes (13 + 10) = 3.14 	imes 5 	imes 23$.$= 15.7 	imes 23 = 361.1 \, cm^2$.

The base of a cone with radius $5 \, cm$ and height $12 \, cm$ is hemispherical. Find the total surface area of the article. $(\pi = 3.14)$ (in $cm^2$)

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