The base current in a transistor circuit chan | vedclass

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(C) The current gain $\beta$ of a transistor in common-emitter configuration is defined as the ratio of the change in collector current to the change

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(C) The current gain $\beta$ of a transistor in common-emitter configuration is defined as the ratio of the change in collector current to the change in base current.$\beta = \frac{\Delta I_C}{\Delta I_B}$Given:$\Delta I_B = 140 \mu A - 45 \mu A = 95 \mu A = 95 	imes 10^{-6} 	ext{ A}$$\Delta I_C = 4.0 	ext{ mA} - 0.2 	ext{ mA} = 3.8 	ext{ mA} = 3.8 	imes 10^{-3} 	ext{ A}$Substituting the values:$\beta = \frac{3.8 	imes 10^{-3}}{95 	imes 10^{-6}}$$\beta = \frac{3800 	imes 10^{-6}}{95 	imes 10^{-6}}$$\beta = 40$

The base current in a transistor circuit changes from $45 \mu A$ to $140 \mu A$. Accordingly,the collector current changes from $0.2 \text{ mA}$ to $4.0 \text{ mA}$. The gain in current is

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