The balancing length for a cell is 560 , cm i | vedclass

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(C) In a potentiometer experiment, the balancing length $l_1$ is proportional to the electromotive force $(E)$ of the cell: $E = k l_1$, where $k$ is

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(C) In a potentiometer experiment, the balancing length $l_1$ is proportional to the electromotive force $(E)$ of the cell: $E = k l_1$, where $k$ is the potential gradient.When an external resistance $R$ is connected in parallel, the terminal potential difference $V$ is given by $V = k l_2$, where $l_2$ is the new balancing length.Given $l_1 = 560 \, cm$ and the change in length is $60 \, cm$, the new balancing length $l_2 = 560 \, cm - 60 \, cm = 500 \, cm$.The formula for internal resistance $r$ is $r = R \left( \frac{E}{V} - 1 ight) = R \left( \frac{l_1}{l_2} - 1 ight) = R \left( \frac{l_1 - l_2}{l_2} ight)$.Substituting the values: $r = 10 \left( \frac{560 - 500}{500} ight) = 10 \left( \frac{60}{500} ight) = 10 	imes 0.12 = 1.2 \, \Omega$.

The balancing length for a cell is $560 \, cm$ in a potentiometer experiment. When an external resistance of $10 \, \Omega$ is connected in parallel to the cell, the balancing length changes by $60 \, cm$. The internal resistance of the cell in ohms is:

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