The specific conductance of a 0.1 N KCl sol | vedclass

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Question

(B) The relationship between specific conductance $(\kappa)$,cell constant $(G^*)$,and resistance $(R)$ is given by the formula: $\kappa = G^* 	imes

Vedclass · Accepted Answer

$0.66$

Vedclass · Answer

(B) The relationship between specific conductance $(\kappa)$,cell constant $(G^*)$,and resistance $(R)$ is given by the formula: $\kappa = G^* 	imes \frac{1}{R}$.Rearranging the formula to solve for the cell constant: $G^* = \kappa 	imes R$.Given values: $\kappa = 0.012 \ \Omega^{-1} \ cm^{-1}$ and $R = 55 \ \Omega$.Substituting the values: $G^* = 0.012 \ \Omega^{-1} \ cm^{-1} 	imes 55 \ \Omega = 0.66 \ cm^{-1}$.

The specific conductance of a $0.1 \ N \ KCl$ solution at $23 \ ^oC$ is $0.012 \ \Omega^{-1} \ cm^{-1}$. The resistance of the cell containing the solution at the same temperature was found to be $55 \ \Omega$. The cell constant will be ............. $cm^{-1}$.

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