The Azimuthal quantum number for the valence | vedclass

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Question

$\mathrm{Ga}^{+}: \mathrm{1s}^{2} \,2 \mathrm{~s}^{2}\, 2 \mathrm{P}^{6}\, 3 \mathrm{~s}^{2} \,3 \mathrm{p}^{6}\, 3 \mathrm{~d}^{10} \,4 \mathrm{~s}^{

Vedclass · Accepted Answer

$0$

Vedclass · Answer

$\mathrm{Ga}^{+}: \mathrm{1s}^{2} \,2 \mathrm{~s}^{2}\, 2 \mathrm{P}^{6}\, 3 \mathrm{~s}^{2} \,3 \mathrm{p}^{6}\, 3 \mathrm{~d}^{10} \,4 \mathrm{~s}^{2}$

last orbital $=$ $\mathrm{s}$

The azimuthal quantum number for the valenceelectrons $(4s-$subshell) of $\mathrm{Ga}+$ ion is zero$(0).$

The Azimuthal quantum number for the valence electrons of $\mathrm{Ga}^{+}$ion is $.....$

(Atomic number of $\mathrm{Ga}=31$ )

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The Azimuthal quantum number for the valence electrons of $\mathrm{Ga}^{+}$ion is $.....$ (Atomic number of $\mathrm{Ga}=31$ )