The average of five consecutive odd integers | vedclass

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Question

(C) Let the five consecutive odd integers be $x, x+2, x+4, x+6,$ and $x+8$.The average of these numbers is given by $\frac{x + (x+2) + (x+4) + (x+6) +

Vedclass · Accepted Answer

$713$

Vedclass · Answer

(C) Let the five consecutive odd integers be $x, x+2, x+4, x+6,$ and $x+8$.The average of these numbers is given by $\frac{x + (x+2) + (x+4) + (x+6) + (x+8)}{5} = 27$.Simplifying the numerator: $\frac{5x + 20}{5} = 27$.$x + 4 = 27$,which implies $x = 23$.The five consecutive odd integers are $23, 25, 27, 29,$ and $31$.The first number is $23$ and the last number is $31$.The product of the first and the last number is $23 	imes 31 = 713$.

The average of five consecutive odd integers is $27$. What is the product of the first and the last number?

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