The audio signal used to modulate 60 sin(2pi | vedclass

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(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is gi

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$25$

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(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is given by $E_m(t) = 15 \sin(300\pi t)$,so the amplitude of the modulating signal is $E_m = 15$.The modulation index (or depth of modulation) $m_a$ is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier wave:$m_a = \frac{E_m}{E_c} = \frac{15}{60} = 0.25$.To express this as a percentage,we multiply by $100$:$m_a = 0.25 	imes 100 = 25\%$.

The audio signal used to modulate $60 \sin(2\pi \times 10^6 t)$ is $15 \sin(300\pi t)$. The depth of modulation is.......$\%$

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