The atomic radii of Li,F,Na,and Si follow the | vedclass

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Question

(D) The correct order is $(d)$.Atomic radius increases down a group and decreases across a period from left to right.$Na$ $(Group \ 1, 	ext{Period }

Vedclass · Accepted Answer

$Na > Li > Si > F$

Vedclass · Answer

(D) The correct order is $(d)$.Atomic radius increases down a group and decreases across a period from left to right.$Na$ $(Group \ 1, 	ext{Period } 3)$ has the largest radius among these because it is in the third period and is an alkali metal.$Li$ $(Group \ 1, 	ext{Period } 2)$ is also an alkali metal but is in the second period,so it is smaller than $Na$.$Si$ $(Group \ 14, 	ext{Period } 3)$ is to the right of $Na$ in the same period,so it is smaller than $Na$ and $Li$.$F$ $(Group \ 17, 	ext{Period } 2)$ is the smallest due to its position at the far right of the second period.Therefore,the order is $Na > Li > Si > F$.

The atomic radii of $Li$,$F$,$Na$,and $Si$ follow the order:

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